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Class 4 (4th Engineer) MET 📅 Nov 2022

Exam Question

(a) Explain about the various speed control methods of DC series motors. (6)

(b) The Armature circuit resistance of an 18.65KW 250V series motor is 0.1Ω. The brush voltage drop is 3V and series field resistance is 0.05Ω. When the motor takes 80A speed is 600 r.p.m. Find the speed when the motor is 100 A.

Reference Answer

### (a) Speed Control Methods of DC Series Motors
The speed of a DC motor is governed by the relationship $$N \propto \frac{E_b}{\phi}$$, where N is the speed, E_b is the back EMF, and Φ is the magnetic flux. The back EMF is given by $$E_b = V - I_a R_a$$, where V is the terminal voltage, I_a is the armature current, and R_a is the armature circuit resistance. Therefore, speed can be controlled by varying either the flux (Φ), the armature circuit resistance (R_a), or the applied voltage (V).
For DC Series motors, the primary methods are:
**1. Flux Control Method (Field Control)**

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