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Class 4 (4th Engineer) SC&S 📅 Aug 2023

Exam Question

The ½ ordinates of a waterplane 120 m long are as follows:

Section AP ½ 1 1½ 2 3 4 5 6 7 8 8½ 9½ FP

½ord 1.2 3.5 5.3 6.8 8.0 8.3 8.5 8.5 8.5. 8.4 8.2 7.9 6.2 3.5 0 m

Calculate: (16)

(a) Waterplane area

(b) Distance of centroid from midships.

Exam question diagram

Reference Answer

To calculate the waterplane area and the longitudinal position of its centroid, Simpson's First Rule and the Trapezoidal Rule will be applied where appropriate, considering the irregular spacing of the given ordinates. The total length of the waterplane is 120 m.
**Interpretation of Given Data:**
The provided data includes 14 station labels (AP, ½, 1, 1½, 2, 3, 4, 5, 6, 7, 8, 8½, 9½, FP) and a sequence of 14 half-ordinates (1.2, 3.5, 5.3, 6.8, 8.0, 8.3, 8.5, 8.5, 8.5, 8.4, 8.2, 7.9, 6.2, 3.5). The final "0 m" in the original input is interpreted as a unit indicator for the preceding value (3.5 m), meaning the half-ordinate at FP is 3.5 m. This interpretation results in 14 ordinates for 10 standard intervals (Station 0 to Station 10).
Let the standard interval (between main stations like 0-1, 1-2, etc.) be $$ h_{std} $$.

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